Question

M*n=-4. m+n=-3 m=? n=?​

Answer 1

m + n = -3

m = -3 - n

m * n = -4

(-3 - n)n = -4

-3n - n^2 = -4

n^2 + 3n - 4 = 0

n^2 + 4n - n - 4 = 0

n(n + 4) - 1(n + 4) = 0

(n - 1)(n + 4) = 0

n = 1 => m = -3 - 1 = -4

n = -4 => m = -3 + 4 = 1

Ответ: (m = -4; n = 1); (m = 1; n = -4)

Answer 2

To solve the system of equations:

1. M * n = -4
2. m + n = -3

We can use substitution or elimination method. Let's solve it using the elimination method:

From equation 2), we can isolate one of the variables in terms of the other: m = -3 - n

Now substitute this value of m into equation 1):

(-3 - n) * n = -4

Expanding the equation: -3n - n^2 = -4

Rearranging the equation: n^2 + 3n - 4 = 0

Now we have a quadratic equation. We can solve it by factoring or using the quadratic formula. Let's use factoring:

(n - 1)(n + 4) = 0

Setting each factor to zero: n - 1 = 0 or n + 4 = 0

Solving for n in each case: n = 1 or n = -4

Now substitute these values of n back into equation 2) to find the corresponding values of m:

For n = 1: m + 1 = -3 m = -3 - 1 m = -4

For n = -4: m + (-4) = -3 m = -3 + 4 m = 1

Therefore, the possible solutions are m = -4 and n = 1, or m = 1 and n = -4.