Question

Човен пливе проти течії річки 6 годин зі швидкістю 12км/год, а на зворотній шлях він затратив 4 години. З якою швидкістю човен подолав зворотній шлях?​

Answer 1

Ответ:

18 км/год

Пошаговое объяснение:

1)12•6=72 км- путь

2)72:4=18 км/год- скорость

Answer 2

Відповідь:

V2=18 км/год.

Покрокове пояснення:

Знайдемо увесь шлях, S=V*t=12*6=72 км

маючи усю відстань(72 км) і маючи час на зворотній шлях, знайдему швидкість назад:  V=S/t⇒72/4=18

Answer 3

Problem Analysis

We are given that a boat travels against the current of a river for 6 hours at a speed of 12 km/h, and it takes 4 hours to travel the same distance in the opposite direction. We need to determine the speed at which the boat traveled on the return trip.

Solution

Let's assume the speed of the current is C km/h and the speed of the boat in still water is B km/h.

When the boat is traveling against the current, its effective speed is reduced by the speed of the current. Therefore, the boat's speed against the current is B - C km/h.

Similarly, when the boat is traveling with the current, its effective speed is increased by the speed of the current. Therefore, the boat's speed with the current is B + C km/h.

We are given that the boat takes 6 hours to travel a certain distance against the current at a speed of 12 km/h. Using the formula distance = speed × time, we can write the equation:

distance = (B - C) × 6

We are also given that the boat takes 4 hours to travel the same distance in the opposite direction. Using the same formula, we can write the equation:

distance = (B + C) × 4

Since the distance traveled is the same in both cases, we can equate the two equations:

(B - C) × 6 = (B + C) × 4

Now we can solve this equation to find the values of B and C.

Let's simplify the equation:

6B - 6C = 4B + 4C

6B - 4B = 6C + 4C

2B = 10C

B = 5C

Therefore, the speed of the boat in still water is 5 times the speed of the current.

To find the speed at which the boat traveled on the return trip, we need to determine the speed of the current. Since we don't have any additional information, we cannot determine the exact speed of the boat on the return trip. However, we can say that the speed of the boat on the return trip is 5 times the speed of the current.

Answer

The speed at which the boat traveled on the return trip is 5 times the speed of the current.