
F(x)=5x+x2 срочно помогите


Ответы на вопрос

Ответ:
x1 = -5
x2 = 0
Пошаговое объяснение:
x^2 + 5x = 0
x (x + 5) = 0
Система: x = 0
x = -5



Function Analysis
The function F(x) can be represented as F(x) = 5x + x^2. This is a quadratic function, where the highest power of the variable x is 2. The general form of a quadratic function is f(x) = ax^2 + bx + c, where a, b, and c are constants.
The given function can be rewritten as F(x) = x^2 + 5x. This form makes it easier to identify the coefficients of the quadratic function. The coefficient of x^2 is 1, the coefficient of x is 5, and the constant term is 0.
Function Properties
The function F(x) = x^2 + 5x has several properties: 1. Vertex: The vertex of the parabola represented by the function F(x) = x^2 + 5x can be calculated using the formula x = -b/2a. In this case, the vertex occurs at x = -b/2a = -5/(2*1) = -5/2.2. Axis of Symmetry: The axis of symmetry of a parabola is a vertical line that divides the parabola into two symmetrical halves. It passes through the vertex of the parabola. For the function F(x) = x^2 + 5x, the axis of symmetry is x = -5/2.
3. Intercepts: The x-intercepts (or roots) of the function F(x) = x^2 + 5x can be found by setting F(x) = 0 and solving for x. The y-intercept can be found by setting x = 0 and evaluating F(x).
4. Concavity: The concavity of the parabola can be determined by the sign of the coefficient of x^2. Since the coefficient of x^2 is positive, the parabola opens upwards, indicating a concave shape.
Conclusion
In conclusion, the function F(x) = x^2 + 5x represents a quadratic function with specific properties related to its vertex, axis of symmetry, intercepts, and concavity. If you have any specific questions about this function or related topics, feel free to ask!

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