Question

СРОЧНО! 57. Два прямоугольных участка имеют одинаковую площадь. Длина первого — 48 м, а ширина — 30 м. Чему равна длина второго участка, если его ширина на 6 м больше ширины первого участка? Запишите решение и ответ. Это задача - её надо решить, а не рисовать 2 прямоугольных участка.

Answer 1

Ответ:

48*30=1440 м - площадь первого участка.

30+6= 36м - ширина второго участка.

1440÷36=40м- длина второго участка.

Answer 2

Ответ:

40 м

Пошаговое объяснение:

30+6=36
48*30:36=1440:36=40

Answer 3

Problem Analysis

We are given two rectangular plots of land with the same area. The length of the first plot is 48 meters and the width is 30 meters. We need to find the length of the second plot, given that its width is 6 meters greater than the width of the first plot.

Solution

Let's denote the length of the second plot as x meters. We know that the area of both plots is the same. The area of a rectangle is calculated by multiplying its length by its width.

The area of the first plot is given by: Area of the first plot = Length of the first plot * Width of the first plot = 48 * 30 = 1440 square meters

The area of the second plot is also equal to 1440 square meters.

Now, let's set up an equation to find the length of the second plot.

The area of the second plot is given by: Area of the second plot = Length of the second plot * Width of the second plot = x * (30 + 6) = 1440 square meters

Simplifying the equation: x * 36 = 1440

Dividing both sides of the equation by 36: x = 1440 / 36 = 40

Therefore, the length of the second plot is 40 meters.

Answer

The length of the second plot is 40 meters.