Question

2(х + 3) = 8 21∙(4 – 6у) = 21у – 42

Answer 1

2(х + 3) = 8
2х+6=8
2х=2
Х=1

2,1*(4-6у)=-42
8,4-12,6у=-42
-12,6у=-42-8,4
-12,6у=-50,4
у=-50,4/(-12,6)
у=4

Answer 2

Let's solve the given equations step by step:

Equation 1: 2(x + 3) = 8

First, distribute the 2 to the terms inside the parentheses: 2x + 6 = 8

Next, subtract 6 from both sides of the equation: 2x + 6 - 6 = 8 - 6 2x = 2

Finally, divide both sides by 2 to solve for x: 2x/2 = 2/2 x = 1

Therefore, the solution to Equation 1 is x = 1.

Equation 2: 21(4 - 6y) = 21y - 42

First, distribute the 21 to the terms inside the parentheses: 84 - 126y = 21y - 42

Next, move all the terms involving y to one side of the equation by adding 126y to both sides: 84 - 126y + 126y = 21y - 42 + 126y 84 = 147y - 42

Next, move the constant term (-42) to the other side by adding 42 to both sides: 84 + 42 = 147y - 42 + 42 126 = 147y

Finally, divide both sides by 147 to solve for y: 126/147 = 147y/147 y = 14/17

Therefore, the solution to Equation 2 is y = 14/17.