Question

Заполните пропуски, используя формулы сокрашеного умноженияа) (_+_)^2=16х^2+24х+_б(а+_)^3=_+6а^2в+_+8в^3пжпжпжпжпжпжп помогите ​

Answer 1

Ответ:

Пошаговое объяснение:

а) (4x + 2)^2 = 16x^2 + 24x + 4

б) (a + 2b)^3 = a^3 + 6a^2b + 12ab^2 + 8b^3

Answer 2

a) (+)^2 = 16x^2 + 24x + _

To solve this equation, we can expand the left side using the formula for squaring a binomial:

(a + b)^2 = a^2 + 2ab + b^2

Comparing it to the given equation, we can deduce that: a^2 = 16x^2 (1) 2ab = 24x (2) b^2 = _

From equation (2), we can solve for b by dividing both sides by 2a: ab = 12x b = (12x) / a

Substituting b into equation (1), we get: (12x / a)^2 = 16x^2 144x^2 / a^2 = 16x^2 144x^2 = 16x^2 * a^2 9 = a^2 a = ±3

Now, substituting the value of a back into equation (2): 2ab = 24x 2(±3)b = 24x ±6b = 24x b = (24x) / ±6 b = ±4x

Therefore, the two possible solutions are: a) (3 + 4x)^2 = 16x^2 + 24x + 16 b) (-3 + 4x)^2 = 16x^2 - 24x + 16

b) (a+_)^3 = _ + 6a^2b + _ + 8b^3

To solve this equation, we can expand the left side using the formula for cubing a binomial:

(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3

Comparing it to the given equation, we can deduce that: a^3 = _ (1) 3a^2b = _ (2) 3ab^2 = 6a^2b b^3 = 8b^3

From equation (2), we can solve for b by dividing both sides by 3a^2: ab = _

Substituting ab into equation (1), we get: (a * _) = _ a^3 * _ = _ _ = _

Since we don't have enough information to determine the specific values, we can only express the equation in terms of the given variables.

The equation becomes: (a + _)^3 = a^3 + 6a^2b + _ + 8b^3

I'm sorry I couldn't provide a specific solution, but without additional information, this is the best representation we can have for the equation.