Question

1,4x + 1 ≥ 0,5x - 1,7 { 2,7x + 10 < 0,9x + 15,4​

Answer 1

Ответ:

xЄ[-3,3>

{x| -3 ≤ x < 3}

Answer 2

Let's solve the given inequality step by step:

1. 1,4x + 1 ≥ 0,5x - 1,7

To simplify the inequality, we can start by subtracting 0.5x from both sides:

1,4x - 0.5x + 1 ≥ -1,7

Combine like terms:

0.9x + 1 ≥ -1,7

Next, subtract 1 from both sides:

0.9x ≥ -1,7 - 1

0.9x ≥ -2.7

Now, divide both sides by 0.9 (the coefficient of x) to isolate x:

x ≥ -2.7 / 0.9

x ≥ -3

So the solution to the first inequality is x ≥ -3.

2. 2,7x + 10 < 0,9x + 15.4

To simplify the inequality, we can start by subtracting 0.9x from both sides:

2,7x - 0.9x + 10 < 15.4

Combine like terms:

1.8x + 10 < 15.4

Next, subtract 10 from both sides:

1.8x < 15.4 - 10

1.8x < 5.4

Now, divide both sides by 1.8 (the coefficient of x) to isolate x:

x < 5.4 / 1.8

x < 3

So the solution to the second inequality is x < 3.

Therefore, the combined solution to the system of inequalities is -3 ≤ x < 3.