Question

(1,2y+18)(1,6-0,2y)=0

Answer 1

Решим уравнение по методу "Нули многочлена":

1.2y + 18 = 0  =>  y = -15

1.6 - 0.2y = 0 =>  y = 8

Таким образом, уравнение имеет два корня: y = -15 и y = 8.

Answer 2

To solve the equation $(1+2y+18)(1.6-0.2y) = 0$, we can use the zero product property, which states that if the product of two quantities is zero, then at least one of the quantities must be zero.

So, we have two factors: $1+2y+18$ and $1.6-0.2y$. To find the values of $y$ that satisfy the equation, we can set each factor equal to zero and solve for $y$.

Setting $1+2y+18 = 0$: $2y + 19 = 0$ $2y = -19$ $y = -\frac{19}{2}$

Setting $1.6 - 0.2y = 0$: $0.2y = 1.6$ $y = \frac{1.6}{0.2}$ $y = 8$

So, the values of $y$ that satisfy the equation $(1+2y+18)(1.6-0.2y) = 0$ are $y = -\frac{19}{2}$ and $y = 8$.