Question

1256. 1) 5x - 8y + 51 = 0, 2,5x + 3y - 23,5 = 0; ​

Answer 1

Пошаговое объяснение:

1) 5х-8у=0,2,5х+3у-23,5=0

Подаємо вираз

{ 5х-8у+51=0

{ 2,5х+3у-23,5=0

Розв'яжемо рівняння

{5х-8у+51=0

{х=-6/5у+9,4

Підставимо значення х

5(-6/5у+9,4)-8у+51=0

Ров'яжемо рівняння

у=7

Підставимо значення у

х=-6/5*7+9,4

Розв'яжемо рівняння

х=1

Відповідь:

(х,у)=(1;7)

Answer 2

It seems there is a typo in the second equation you provided. I will assume you meant "2.5x + 3y - 23.5 = 0."

To solve the system of equations:

1. 5x - 8y + 51 = 0
2. 2.5x + 3y - 23.5 = 0

We can use either the substitution method or the elimination method. I will demonstrate the elimination method:

First, let's multiply the second equation by 2 to eliminate the decimal:

2 * (2.5x + 3y - 23.5) = 0 5x + 6y - 47 = 0

Now, we have the following system of equations:

1. 5x - 8y + 51 = 0
2. 5x + 6y - 47 = 0

To eliminate the x-term, we can subtract equation 1 from equation 2:

(5x + 6y - 47) - (5x - 8y + 51) = 0 5x + 6y - 47 - 5x + 8y - 51 = 0 14y - 98 = 0

Now, we have a new equation:

3. 14y - 98 = 0

We can solve equation 3 for y:

14y = 98 y = 98 / 14 y = 7

Now that we have the value of y, we can substitute it back into either equation 1 or equation 2. Let's use equation 1:

5x - 8(7) + 51 = 0 5x - 56 + 51 = 0 5x - 5 = 0 5x = 5 x = 1

Therefore, the solution to the system of equations is x = 1 and y = 7.