Question

Log1/7 49 решение плис

Answer 1

-2 
при возведение логарифма 17 в -2 степень,получим 49

Answer 2

Log1/7 49 = 2, because 1/7 to the power of 2 equals 49. This can also be written as log1/7 49 = log1/7 7^2, because 49 is the same as 7^2. Therefore, using the logarithmic property of exponentiation, log1/7 7^2 = 2 log1/7 7, and since log1/7 7 = 1, we get log1/7 7^2 = 2.