Question

В) 2(3x+4)+(6x+8)=4(5x-2)-(5x+8) г) 8(4-3y)-(7-2y)=-(6+3y)+8(y-2)

Answer 1

В) раскрываем скобки
6х+8+6х+8=20х-8-5х-8
переносим х в левую часть, а числовые значение в правую, меняем знаки
6х+6х-20х+5х=-8-8-8-8
считаем
-3х=-32
х=10целых2/3
г) 32-24у-7+2у=-6-3у+8у-16
-27у=-47
у=1целая20/27

Answer 2

a) Let's start by simplifying both sides of the equation:

2(3x+4)+(6x+8)=4(5x-2)-(5x+8)

6x+8+6x+8=20x-8-5x-8

12x+16=15x-16

Now, let's isolate the variable (x) to one side of the equation by subtracting 12x and adding 16 to both sides:

12x+16-12x+12x=15x-12x-16+16

16=3x

Finally, we solve for x by dividing both sides by 3:

x=16/3

Therefore, the solution to the equation 2(3x+4)+(6x+8)=4(5x-2)-(5x+8) is x=16/3.

b) Let's begin by simplifying both sides of the equation:

8(4-3y)-(7-2y)=-(6+3y)+8(y-2)

32-24y-7+2y=-6-3y+8y-16

25-22y=-6+5y-16

25-22y=-22+5y

Now, let's isolate the variable (y) to one side of the equation by adding 22y and subtracting 25 from both sides:

25-22y+22y=-22+5y+22y-25

25=27y-22

Finally, we solve for y by adding 22 to both sides and then dividing by 27:

y=(25+22)/27

y=47/27

Therefore, the solution to the equation 8(4-3y)-(7-2y)=-(6+3y)+8(y-2) is y=47/27.