Question

X^2-3xy+5y^2+3x+y+5=0 найти x+y=?

Answer 1

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Answer 2

To solve the equation X^2-3xy+5y^2+3x+y+5=0 and find the value of x+y, we can use the following steps:

1. Rewrite the equation in terms of one variable, either x or y.
2. Solve for that variable using the quadratic formula.
3. Once we have a value for one variable, we can substitute it into the other variable to find the value of the sum x+y.

Let's begin by rewriting the equation in terms of x:

X^2-3xy+5y^2+3x+y+5=0

x^2 + (3 - y)x + 5y^2 + y + 5 = 0 (grouping the x terms together)

Now we can use the quadratic formula to solve for x:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 1, b = 3 - y, and c = 5y^2 + y + 5.

Substituting these values into the formula, we get:

x = (- (3 - y) ± sqrt((3 - y)^2 - 4(1)(5y^2 + y + 5))) / 2(1)

Simplifying:

x = (-3 + y ± sqrt(4y^2 + 2y + 1 - 20y^2 - 4y - 20)) / 2

x = (-3 + y ± sqrt(-16y^2 - 2y - 19)) / 2

Since the discriminant is negative, there are no real solutions for x. Therefore, the equation X^2-3xy+5y^2+3x+y+5=0 does not have any real solutions, and we cannot find a value for x+y.