Question

-(-3y-a)+(-a+2y)= 2) -(-15k+1)-2(30k+5)= 3) 32(3k-y)-21(5k+2y)=. ​

Answer 1

Ответ:

Пошаговое объяснение:

1) -(-3y-a)+(-a+2y)= 3y + a - a + 2y = 5y

2) -(-15k+1)-2(30k+5)= 15k - 1 - 60k - 10 = -45k - 11

3) 32(3k-y)-21(5k+2y)=. ​96k - 32y - 105k - 42y = -9k - 74y

Answer 2

1) 3у+а-а+2у=5у

2)15к-1-60к-10=-45к-11

3)96к-32у-105к-42у=-9к-74у

Answer 3

Starting with the first equation:

-(-3y-a) + (-a+2y)

= 3y + a - a + 2y [distributing the negative sign]

= 5y

Therefore, the solution is:

5y

Moving on to the second equation:

-(-15k+1) - 2(30k+5)

= 15k - 1 - 60k - 10 [distributing the negative sign and using the distributive property]

= -45k - 11

Therefore, the solution is:

-45k - 11

Finally, let's look at the third equation:

32(3k-y) - 21(5k+2y)

= 96k - 32y - 105k - 42y [distributing the coefficients]

= -9k - 74y

Therefore, the solution is:

-9k - 74y