Question

10*(3L-2)-(45L+18)/3+(11-L)*5=25

Answer 1

$10\cdot(3L-2)-(45L+18):3+(11-L)\cdot5=25$

 

$30L-20-15L-6+55-5L=25$

 

$30L-20-15L-6+55-5L-25=0$

 

$(30L-15L-5L)+(-20-6+55-25)=0$

 

$10L+4=0$

 

$10L=-4$

 

$L=-4:10$

 

$L=-0,4$

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$10\cdot(3\cdot(-0,4)-2)-(45\cdot(-0,4)+18):3+(11-(-0,4))\cdot5=25$

 

$10\cdot(-1,2-2)-(-18+18):3+(11+0,4)\cdot5=25$

 

$10\cdot(-3,2)+0+11,4\cdot5=25$

 

$-32+57=25$

 

$25=25$

Answer 2

Let's simplify the expression step by step:

Starting with the left-hand side:

10*(3L - 2) - (45L + 18)/3 + (11 - L)*5

= 30L - 20 - (15L + 6) + 55 - 5L // Using distributive property

= 30L - 15L - 5L - 20 - 6 + 55 // Rearranging terms

= 10L + 29 // Simplifying the expression

Now, we have simplified the left-hand side of the equation to 10L + 29.

We can now set this expression equal to 25 and solve for L:

10L + 29 = 25

10L = -4

L = -4/10

L = -0.4

Therefore, the value of L that satisfies the equation is -0.4.