Question

1)√x=x-2 2)√8-x-√1+x=3

Answer 1

Вот тут решение первого второе пограмотней напиши

Answer 2

1. To solve the equation √x = x - 2:

First, we can square both sides to get rid of the square root:

√x = x - 2

(√x)^2 = (x - 2)^2

x = x^2 - 4x + 4

Now, we can move all the terms to one side of the equation:

x^2 - 5x + 4 = 0

This is a quadratic equation that we can solve using factoring or the quadratic formula:

x^2 - 5x + 4 = 0

(x - 4)(x - 1) = 0

x = 4 or x = 1

However, we need to check that these solutions work in the original equation, since we squared both sides, which could have introduced extraneous solutions. Checking both solutions, we find that only x = 4 satisfies the original equation:

√4 = 4 - 2

2 = 2

Therefore, the solution to the equation √x = x - 2 is x = 4.

2. To solve the equation √8 - x - √1 + x = 3:

We can first simplify the equation by combining like terms on the left side:

√8 - x - √1 + x = 3

√8 - √1 - x + x = 3

√7 = 3

This is a contradiction, since the square root of any number cannot be negative. Therefore, there is no solution to the equation √8 - x - √1 + x = 3.