Question

F(x)=1+3x-x^2 найти f"(x)>0

Answer 1

F(x)=1+3x-x^болше чем 90

Answer 2

To find the second derivative of the function f(x) = 1 + 3x - x^2 and determine where it is greater than zero, we need to first find the first derivative and then differentiate it again.

f(x) = 1 + 3x - x^2

f'(x) = 3 - 2x

f''(x) = -2

Since the second derivative is a constant, f''(x) is always less than zero, meaning it is never greater than zero. Therefore, the function f(x) = 1 + 3x - x^2 does not have any points of inflection, and its graph is always concave down.

In summary, f''(x) = -2 for all values of x, and f(x) = 1 + 3x - x^2 is always concave down.