Question

Помогите пж 1. x/5-4=x/3 2. у/3=у/2-7 3. х/2-1=х/3-4 4. z/5=z/10+1 5. u/2-3=u/4+5 + решение уровнения

Answer 1

1. Х/5 - Х/3 = 4          3Х/15 - 5Х/15 = 4      - 2Х/15 = 4       - 2Х = 15 х 4 = 60
    Х = 60/- 2        Х = - 30
2. У/3 -У/2 = - 7         2У/6 - 3У/6 = - 7        -У/6 = - 7    - У = -7 х 6 = - 42
    У = 42
3. Х/2 - Х/3 = 1 - 4      3Х/6 - 2Х/6 = - 3       Х/6 = - 3      Х = - 3 х 6 = - 18
    Х = - 18
4. Z/5 - Z/10 = 1          2Z/10 - Z/10 = 1     Z/10 = 1     Z = 1 х 10
    Z = 10
5. U/2 - U/4 = 5 + 3      2U/4 - U/4 = 8       U/4 = 8      U = 8 х 4
    U = 32

Answer 2

1. x/5-4=x/3

To solve this equation, we can start by getting rid of the fractions by multiplying both sides of the equation by the least common multiple (LCM) of 5 and 3, which is 15:

15(x/5-4) = 15(x/3) 3x - 60 = 5x 2x = 60 x = 30

Therefore, the solution to the equation is x = 30.

2. у/3=у/2-7

To solve this equation, we can start by getting rid of the fractions by multiplying both sides of the equation by the LCM of 3 and 2, which is 6:

6(у/3) = 6(у/2-7) 2у - 42 = 3у у = 42

Therefore, the solution to the equation is у = 42.

3. х/2-1=х/3-4

To solve this equation, we can start by getting rid of the fractions by multiplying both sides of the equation by the LCM of 2 and 3, which is 6:

6(х/2-1) = 6(х/3-4) 3x - 6 = 2x - 24 x = -18

Therefore, the solution to the equation is x = -18.

4. z/5=z/10+1

To solve this equation, we can start by getting rid of the fractions by multiplying both sides of the equation by the LCM of 5 and 10, which is 50:

50(z/5) = 50(z/10+1) 10z = 5z + 50 5z = 50 z = 10

Therefore, the solution to the equation is z = 10.

5. u/2-3=u/4+5

To solve this equation, we can start by getting rid of the fractions by multiplying both sides of the equation by the LCM of 2 and 4, which is 8:

8(u/2-3) = 8(u/4+5) 4u - 24 = 2u + 40 2u = 64 u = 32

Therefore, the solution to the equation is u = 32.