Question

1)2(х+3)=х+13 2)4(5-х)=3х-1 3)3(х-2)=х+4 4)5(х-1)=4х+3

Answer 1

2(х+3)=х+13
2x+6=x+13
2x-x=13-6
x=7
Ответ: х= 7 

4(5-х)=3х-1
20-4x=3x-1
-4x-3x=-1-20
-7x=-21
x=3
Ответ: х= 3 

3(х-2)=х+4
3x-6=x+4
3x-x=4+6
2x=10
x=5
Ответ: х= 5 

5(х-1)=4х+3
5x-5=4x+3
5x-4x=3+5
x=8
Ответ:х=8 

Answer 2

First, distribute the 2 on the left side of the equation:

2(x + 3) = 2x + 6

Now the equation is:

2x + 6 = x + 13

Subtract x from both sides:

x + 6 = 13

Subtract 6 from both sides:

x = 7

Therefore, the solution is x = 7.

First, distribute the 4 on the left side of the equation:

20 - 4x = 3x - 1

Add 4x to both sides:

20 = 7x - 1

Add 1 to both sides:

21 = 7x

Divide both sides by 7:

x = 3

Therefore, the solution is x = 3.

First, distribute the 3 on the left side of the equation:

3x - 6 = x + 4

Subtract x from both sides:

2x - 6 = 4

Add 6 to both sides:

2x = 10

Divide both sides by 2:

x = 5

Therefore, the solution is x = 5.

First, distribute the 5 on the left side of the equation:

5x - 5 = 4x + 3

Subtract 4x from both sides:

x - 5 = 3

Add 5 to both sides:

x = 8

Therefore, the solution is x = 8.