Question

Решите уравнения пжлст |1 + x| = 0|2 + x| = 0|3 + x| = 1.5|7 - y| = -2|2 - 3x| = 0|4 + 5x| = 02.5 |3y|= 15|8x + 12| = 20|15x + 10| = 5

Answer 1

Вот решение. Удачи в учебе!

Answer 2

1. |1 + x| = 0 The absolute value of any real number is non-negative, so it can never be equal to zero unless the number itself is zero. Therefore, the only solution is x = -1.

2. |2 + x| = 0 Similar to the previous equation, the absolute value of any real number is non-negative and can only be equal to zero if the number itself is zero. Therefore, the solution is x = -2.

3. |3 + x| = 1.5 The equation has two cases: 3 + x = 1.5 and -(3 + x) = 1.5. Solving the first case: 3 + x = 1.5 x = -1.5 Solving the second case: -(3 + x) = 1.5 -3 - x = 1.5 x = -4.5 Therefore, the solutions are x = -1.5 and x = -4.5.

4. |7 - y| = -2 The absolute value of any real number is always non-negative and can never be equal to a negative number. Therefore, there are no solutions to this equation.

5. |2 - 3x| = 0 Similar to equations 1 and 2, the absolute value of any real number is non-negative and can only be equal to zero if the number itself is zero. Therefore, the solution is x = 2/3.

6. |4 + 5x| = 0 Similar to equation 5, the solution is x = -4/5.

7. 2.5 |3y| = 15 Simplifying the equation: |3y| = 6 The absolute value of any real number is always non-negative, so it can either be equal to the positive or negative value of 6. Therefore, the solutions are y = 2 and y = -2.

8. |8x + 12| = 20 The equation has two cases: 8x + 12 = 20 and -(8x + 12) = 20. Solving the first case: 8x + 12 = 20 x = 1.5 Solving the second case: -(8x + 12) = 20 -8x - 12 = 20 x = -4.5 Therefore, the solutions are x = 1.5 and x = -4.5.

9. |15x + 10| = 5 The equation has two cases: 15x + 10 = 5 and -(15x + 10) = 5. Solving the first case: 15x + 10 = 5 x = -0.333 Solving the second case: -(15x + 10) = 5 -15x - 10 = 5 x = -1 Therefore, the solutions are x = -0.333 and x = -1.