Question

27^2\3 - 16^1\4 вичислите

Answer 1

Решение задания смотри на фотографии

Answer 2

${27}^{ \frac{2}{3} } - {16}^{ \frac{1}{4} } = ( {3}^{3})^{ \frac{2}{3} } - ( {2}^{4} )^{ \frac{1}{4} } = {3}^{2} - 2 = 9 - 2 = 7$

Answer 3

To compute the expression 27^(2/3) - 16^(1/4), we need to evaluate the powers first and then perform the subtraction.

Let's start with the first term, 27^(2/3):

27^(2/3) = (cube root of 27)^2

The cube root of 27 is 3, so we have:

(3)^2 = 9

Now let's calculate the second term, 16^(1/4):

16^(1/4) = fourth root of 16

The fourth root of 16 is 2, so we have:

2

Finally, we can subtract the two results:

9 - 2 = 7

Therefore, 27^(2/3) - 16^(1/4) is equal to 7.