Question

(х+7)х=18 23-4(3х+8)=1-17х

Answer 1

Раскроем скобки :
$x^{2} +7x-18=0;$
Вычислим дискриминант :
$D = 49 + 72 = 121$
Найдем корни уравнения :
$x_{1} =(-7-11)/2 = -9 ; x_{2} =(-7+11)/2 = 2$
Запишем ответ : {-9}, {2}

Решим второе уравнение. Раскроем скобки :
23 - 12*х - 32 = 1 - 17*х
5*х = 10
х = 2

Answer 2

Let's solve the given equations step by step:

Equation 1: (х+7)х = 18

Expanding the equation, we get: x^2 + 7x = 18

Rearranging the equation to bring all terms to one side: x^2 + 7x - 18 = 0

Now we can factorize the quadratic equation: (x + 9)(x - 2) = 0

Setting each factor equal to zero: x + 9 = 0 or x - 2 = 0

Solving for x in each case: x = -9 or x = 2

So the solutions to Equation 1 are x = -9 and x = 2.

Equation 2: 23 - 4(3x + 8) = 1 - 17x

Expanding and simplifying the equation: 23 - 12x - 32 = 1 - 17x

Combining like terms: -12x - 9 = -17x

Adding 17x to both sides: 5x - 9 = 0

Adding 9 to both sides: 5x = 9

Dividing by 5: x = 9/5

Therefore, the solution to Equation 2 is x = 9/5 or x = 1.8.

To summarize: Equation 1: x = -9 or x = 2 Equation 2: x = 9/5 or x = 1.8