Question

2sin^2 a-1/sina+cosa

Answer 1

Вооот решение , там всё просто))

Answer 2

To simplify the expression (2sin^2(a) - 1) / (sin(a) + cos(a), we can start by factoring the numerator:

2sin^2(a) - 1 = (2sin(a))^2 - 1 = (2sin(a) + 1)(2sin(a) - 1).

Now, let's rewrite the denominator as a single term:

sin(a) + cos(a) = sin(a) + cos(a) * (sin(a) / sin(a)) = sin(a) + sin(a)cos(a) / sin(a) = sin(a) (1 + cos(a)) / sin(a) = (1 + cos(a)).

Now, substituting the numerator and denominator back into the expression, we have:

(2sin^2(a) - 1) / (sin(a) + cos(a)) = [(2sin(a) + 1)(2sin(a) - 1)] / (1 + cos(a)).

Therefore, the simplified form of the expression is [(2sin(a) + 1)(2sin(a) - 1)] / (1 + cos(a)).