Question

........................................................... |2x+3|=1..........................................

Answer 1

|2x+3|=1
раскрывая модуль получаем
2х+3=1
2х=1-3
2х=-2
х=-2:2
х=-1
либо
2х+3=-1
2х=-1-3
2х=-4
х=-4:2
х=-2
ответ: -2;-1

Answer 2

To solve the absolute value equation |2x + 3| = 1, we can break it down into two separate cases and solve for each case individually.

Case 1: 2x + 3 is positive (2x + 3 > 0) In this case, the absolute value of 2x + 3 is simply 2x + 3 itself. So we can rewrite the equation as: 2x + 3 = 1

Subtract 3 from both sides: 2x = 1 - 3 2x = -2

Divide both sides by 2: x = -2/2 x = -1

Case 2: 2x + 3 is negative (2x + 3 < 0) In this case, the absolute value of 2x + 3 is -(2x + 3). So we can rewrite the equation as: -(2x + 3) = 1

Distribute the negative sign: -2x - 3 = 1

Add 3 to both sides: -2x = 1 + 3 -2x = 4

Divide both sides by -2: x = 4/(-2) x = -2

Therefore, the solution to the absolute value equation |2x + 3| = 1 is x = -1 and x = -2.