Question

1)(7x-2)^2+28x(3x+1)^2-21x2)a^3+2a+a^2+2

Answer 1

1)(7х-2)^2+28х=49х^2-28х+4+28х=49х^2+4
(3х+1)^2-21х=9х^2+6х+1-21х=9х^2-15х+1
2)а^3+2а+а^2+2=а(а^2+2)+а^2+2=(а^2+2)(а+1)

Answer 2

To simplify the given expression, let's start by expanding the terms:

(7x - 2)^2 = (7x - 2)(7x - 2) = 49x^2 - 14x - 14x + 4 = 49x^2 - 28x + 4

(3x + 1)^2 = (3x + 1)(3x + 1) = 9x^2 + 3x + 3x + 1 = 9x^2 + 6x + 1

Let's substitute these expanded terms back into the expression:

(49x^2 - 28x + 4) + 28x(9x^2 + 6x + 1) - 21x^2(a^3) + 2a + a^2 + 2

Next, we can distribute the coefficients:

49x^2 - 28x + 4 + (28x)(9x^2) + (28x)(6x) + (28x)(1) - 21x^2(a^3) + 2a + a^2 + 2

Now, let's simplify each term:

49x^2 - 28x + 4 + 252x^3 + 168x^2 + 28x - 21x^2(a^3) + 2a + a^2 + 2

Combine like terms:

252x^3 + 49x^2 - 21x^2(a^3) + 168x^2 - 28x - 28x + 2a + a^2 + 4 + 2

Finally, rearrange the terms:

252x^3 + (49x^2 - 21x^2(a^3) + 168x^2) - (28x + 28x) + (a^2 + 2a + 4 + 2)

This is the simplified form of the given expression:

252x^3 + (49 - 21(a^3) + 168)x^2 - 56x + (a^2 + 2a + 6)