Question

133÷(38х-95)=7 ; 15×(53-8х)=75 ; (6х-29)×8=104

Answer 1

133:(38x-95)=7
38x=133:7
38x=19
38x=19+95
38x=114
x=114:38
x=3
133:(38×3-95)=7
7=7
15×(53-8x)=75
8x=75:15
8x=5
8x=53-5
8x=48
x=48:8
x=6
15×(53-8×6)=75
75=75
(6x-29)×8=104
6x=104:8
6x=13
6x=13+29
6x=42
x=42:6
x=7
(6×7-29)×8=104
104=104

Answer 2

To solve these equations, I will go through each one step by step:

1. 133÷(38x-95) = 7

To solve this equation, we need to isolate the variable on one side of the equation. Let's start by multiplying both sides of the equation by (38x-95):

133 = 7(38x-95)

Now, distribute 7 to the terms inside the parentheses:

133 = 266x - 665

Move -665 to the other side of the equation:

133 + 665 = 266x

798 = 266x

Finally, divide both sides of the equation by 266:

798 ÷ 266 = x

x = 3

So the solution to the first equation is x = 3.

2. 15×(53-8x) = 75

Start by simplifying the equation inside the parentheses:

15 × 53 - 15 × 8x = 75

Now, multiply 15 by 53 and 15 by 8x:

795 - 120x = 75

Move 75 to the other side of the equation:

795 - 75 = 120x

720 = 120x

Divide both sides of the equation by 120:

720 ÷ 120 = x

x = 6

Therefore, the solution to the second equation is x = 6.

3. (6x-29) × 8 = 104

Multiply 8 by the expression inside the parentheses:

8(6x-29) = 104

Distribute 8 to the terms inside the parentheses:

48x - 232 = 104

Move -232 to the other side of the equation:

48x = 104 + 232

48x = 336

Divide both sides of the equation by 48:

336 ÷ 48 = x

x = 7

Hence, the solution to the third equation is x = 7.

To summarize:

1. x = 3
2. x = 6
3. x = 7