Question

(6а-1)(6а+1) = 4а(9а+2)-1

Answer 1

(6а-1)(6а+1)-4а (9а+2)=-1
36а²-1 -36а²-8а=-1
-8а=1-1
-8а=0
а=0

Answer 2

Let's simplify both sides of the equation to determine if they are equal:

Starting with the left side:

(6a - 1)(6a + 1)

Using the distributive property, we can expand this expression as follows:

= 6a * 6a + 6a * 1 - 1 * 6a - 1 * 1 = 36a^2 + 6a - 6a - 1 = 36a^2 - 1

Now let's simplify the right side:

4a(9a + 2) - 1

Using the distributive property again:

= 4a * 9a + 4a * 2 - 1 = 36a^2 + 8a - 1

Comparing the simplified expressions from both sides of the equation, we have:

36a^2 - 1 = 36a^2 + 8a - 1

The -1 terms cancel out on both sides, so we are left with:

36a^2 = 36a^2 + 8a

Now, subtracting 36a^2 from both sides:

0 = 8a

Dividing both sides by 8:

0/8 = a

So the solution is a = 0.