Question

27×81^sin-12×9^sin+1

Answer 1

Решение во вложении--------------------

Answer 2

To calculate the expression 27 × 81^sin(-12) × 9^sin(1), we'll break it down step by step:

Step 1: Evaluate the exponentials: 81^sin(-12) = 81 raised to the power of the sine of -12 degrees. Since sine is a periodic function, we can convert the angle to its equivalent positive angle within one period. sin(-12) = sin(360 - 12) = sin(348) ≈ -0.5591939385 (rounded to 10 decimal places).

9^sin(1) = 9 raised to the power of the sine of 1 degree. sin(1) ≈ 0.0174524064 (rounded to 10 decimal places).

Step 2: Substitute the values into the expression: 27 × 81^sin(-12) × 9^sin(1) becomes 27 × (81^-0.5591939385) × (9^0.0174524064).

Step 3: Evaluate the exponentials using a calculator: 81^-0.5591939385 ≈ 0.2054071216 (rounded to 10 decimal places). 9^0.0174524064 ≈ 1.0157678447 (rounded to 10 decimal places).

Step 4: Multiply the values together: 27 × 0.2054071216 × 1.0157678447 ≈ 5.616262 (rounded to 6 decimal places).

Therefore, 27 × 81^sin(-12) × 9^sin(1) is approximately equal to 5.616262.