Question

В равнобедренном треугольнике АВС ВС = 40 см, AC = 20 см. Найдите периметр треугольника. Ответ дайте в сантиметрах.

Answer 1

Р=АВ+ВС+СА
Т.к. треугольник АВС - равнобедренный, то АВ=ВС=40см, АС=20 см
Р=40см+40см+20см
Р=100см

Answer 2

P=2a+b P=20*2+40 P=80 см

Answer 3

Perimeter of an Isosceles Triangle

To find the perimeter of a triangle, we need to add the lengths of all three sides. In the case of an isosceles triangle, two sides have the same length, while the third side is different.

In the given isosceles triangle ABC, we are given that side BC has a length of 40 cm and side AC has a length of 20 cm.

To find the perimeter, we need to determine the length of side AB. Since ABC is an isosceles triangle, we can assume that side AB is equal to side BC.

Therefore, the perimeter (P) of the triangle ABC can be calculated as:

P = AB + BC + AC

Substituting the given values:

P = AB + 40 cm + 20 cm

To find the value of AB, we can subtract the length of AC from BC:

AB = BC - AC

AB = 40 cm - 20 cm

AB = 20 cm

Now, we can substitute the value of AB into the perimeter equation:

P = 20 cm + 40 cm + 20 cm

P = 80 cm

Therefore, the perimeter of the triangle ABC is 80 cm.