Question

В треугольнике АБC угол С 90 градусов ВС=6 корней из 6, АС=3 Найти cosA

Answer 1

CosА=AC/AB=3/корень (9+216)=3/15=0,2

Answer 2

Task: Find cosA in triangle ABC, where angle C is 90 degrees, BC = 6√6, and AC = 3.

To find cosA in triangle ABC, we can use the cosine formula, which relates the sides and angles of a triangle. The formula is as follows:

cosA = (BC^2 + AC^2 - AB^2) / (2 * BC * AC)

Given that angle C is 90 degrees, we can use the Pythagorean theorem to find the length of side AB:

AB^2 = BC^2 + AC^2

Let's substitute the given values into the formula and solve for cosA.

Step 1: Find the length of side AB using the Pythagorean theorem.

AB^2 = BC^2 + AC^2 AB^2 = (6√6)^2 + 3^2 AB^2 = 216 + 9 AB^2 = 225 AB = 15

Step 2: Substitute the values into the cosine formula and solve for cosA.

cosA = (BC^2 + AC^2 - AB^2) / (2 * BC * AC) cosA = ((6√6)^2 + 3^2 - 15^2) / (2 * (6√6) * 3) cosA = (216 + 9 - 225) / (2 * 6√6 * 3) cosA = 0 / (36√6) cosA = 0

Therefore, cosA is equal to 0 in triangle ABC.

Please let me know if you need any further assistance!