Question

В случайном эксперименте бросают две игральные кости. Найдите вероятность того, что в сумме выпадет менее 7 очков. Результат округлите до сотых.

Answer 1

Решение: Всего возможных комбинаций при вбрасывании двух кубиков: 6 * 6 = 36.
Из них благоприятные исходы можно перечислить:
1+6
6+1
2+5
5+2
3+4
4+3
Таким образом, всего благоприятных исходов 6.
Вероятность найдем, как отношение числа 6 благоприятных исходов к числу всех возможных комбинаций 36.
6/36 = 0,16666…
Округлим до сотых. Ответ: 0, 17

Answer 2

Calculation of Probability

To find the probability that the sum of the two dice is less than 7, we need to determine the number of favorable outcomes and the total number of possible outcomes.

The favorable outcomes are the combinations of dice rolls that result in a sum less than 7. We can calculate this by listing all the possible combinations and counting the ones that meet the condition.

According to the search results, there are 10 favorable outcomes: (1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1), (1, 4), (4, 1), (2, 3), and (3, 2).

The total number of possible outcomes is the product of the number of outcomes for each die. Since each die has 6 possible outcomes, the total number of outcomes is 6 * 6 = 36.

Therefore, the probability of getting a sum less than 7 is given by the ratio of favorable outcomes to total outcomes:

Probability = Number of Favorable Outcomes / Total Number of Outcomes

Probability = 10 / 36 = 0.2778 (rounded to the nearest hundredth)

So, the probability that the sum of the two dice is less than 7 is approximately 0.28.

Please note that the calculation assumes fair dice and equally likely outcomes for each roll.