Question

Ac пересекает bd в точке k ak=kc,bk=kd ac=8 bd = 6 ab =5 найти P∆ kcd ?

Answer 1

Вторая диагональ ромба AC= 2*Корень(25-9)=2*4 = 8 см
Расстояние от точки К до вершин ромба
AK=CK = Корень (8*8+4*4)= Корень (80)
KB=KD= Корень (8*8+3*3)= Корень (73)

Answer 2

Problem Analysis

We are given a triangle ABC with points D and K on sides AB and BC, respectively. It is known that AK = KC, BK = KD, AC = 8, BD = 6, and AB = 5. We need to find the perimeter of triangle KCD.

Solution

To find the perimeter of triangle KCD, we need to find the lengths of sides KC, CD, and KD.

Let's start by finding the length of side KC. Since AK = KC, we can divide the length of side AC by 2 to find KC. Given that AC = 8, we have KC = AC/2 = 8/2 = 4.

Next, let's find the length of side CD. To do this, we can use the fact that the sum of the lengths of opposite sides of a quadrilateral is equal. In this case, we can use the fact that AB + CD = AC + BD. Given that AB = 5 and BD = 6, we have 5 + CD = 8 + 6. Solving this equation, we find CD = 9.

Finally, let's find the length of side KD. Since BK = KD, we can divide the length of side BD by 2 to find KD. Given that BD = 6, we have KD = BD/2 = 6/2 = 3.

Now that we have the lengths of sides KC, CD, and KD, we can find the perimeter of triangle KCD by adding these lengths together. The perimeter P∆ KCD = KC + CD + KD = 4 + 9 + 3 = 16.

Therefore, the perimeter of triangle KCD is 16.

Answer

The perimeter of triangle KCD is 16.