Question

Решите очень срочно надо! Два заряда q1= 2*10^-7 Кл и q2=-2*10^-7Кл расположены в керосине на расстоянии 0,2 м друг от друга. Какова напряженность поля в точке находящейся между зарядами на растоянии 0,08 м от положительного заряда на линии соединяющей центры зарядов. Заранее спасибо!

Answer 1

отдельные формулы

Е=k*q/ d^2

E= сигма/(2*'эпсила*эпсила0)

сигма= q/s (поверхностная плотность заряда)

F кулона в среде=( k/эпсила)* (|q1|*|q1|)/ r^2

 сейчас нет времени решить...

Answer 2

Calculation of Electric Field Intensity

To calculate the electric field intensity at a point between two charges, we can use the formula:

E = (k * q) / r^2

Where: - E is the electric field intensity - k is the electrostatic constant (approximately 9 x 10^9 Nm^2/C^2) - q is the charge - r is the distance from the charge to the point where the electric field is being calculated

In this case, we have two charges, q1 = 2 * 10^-7 C and q2 = -2 * 10^-7 C, located in kerosene at a distance of 0.2 m from each other.

We want to find the electric field intensity at a point located 0.08 m from the positive charge (q1) on the line connecting the centers of the charges.

Let's calculate the electric field intensity using the given values:

For q1: - Charge (q) = 2 * 10^-7 C - Distance (r) = 0.08 m

For q2: - Charge (q) = -2 * 10^-7 C - Distance (r) = 0.12 m (0.2 m - 0.08 m)

Using the formula mentioned above, we can calculate the electric field intensity at the given point.

E1 = (k * q1) / r1^2 E2 = (k * q2) / r2^2

Let's substitute the values and calculate:

E1 = (9 * 10^9 Nm^2/C^2 * 2 * 10^-7 C) / (0.08 m)^2 E2 = (9 * 10^9 Nm^2/C^2 * -2 * 10^-7 C) / (0.12 m)^2

Calculating the above expressions, we find:

E1 = 45 N/C E2 = -20 N/C

Therefore, the electric field intensity at the given point is 45 N/C in the direction of the positive charge (q1) and -20 N/C in the direction of the negative charge (q2)