Question

Дано:ABCD-параллелограмм DC=18 AD=14 угол В=150 градусов Найти площадь параллелограмма

Answer 1

Площадь параллелограмма равна 126 см квадратных

Answer 2

Площадь параллелограмма - S=a*b*sinα, где а и b стороны, α - угол между ними;
S=18*14*sin150=252/2=126 ед².

Answer 3

I can help you with your geometry question.

The area of a parallelogram is given by the formula $S = a \cdot b \cdot \sin \alpha$, where $a$ and $b$ are the lengths of the adjacent sides and $\alpha$ is the angle between them. In this case, we have $a = DC = 18$, $b = AD = 14$, and $\alpha = \angle B = 150^{\circ}$. Therefore, the area of the parallelogram is:

$$S = 18 \cdot 14 \cdot \sin 150^{\circ}$$ $$S = 252 \cdot \frac{1}{2}$$ $$S = 126$$

The area of the parallelogram is 126 square units. This answer agrees with the one given by [this website](https://online-otvet.ru/geometria/5cea9b7f96f4e19a294f4f81). You can also check out [this lesson](https://uchitel.pro/%D1%83%D1%80%D0%BE%D0%BA-7-%D1%80%D0%B5%D1%88%D0%B5%D0%BD%D0%B8%D0%B5-%D0%B7%D0%B0%D0%B4%D0%B0%D1%87-%D0%BF%D0%B0%D1%80%D0%B0%D0%BB%D0%BB%D0%B5%D0%BB%D0%BE%D0%B3%D1%80%D0%B0%D0%BC%D0%BC/) or [this problem set](https://infourok.ru/reshenie-osnovnih-zadach-po-teme-parallelogramm-3861651.html) for more examples and explanations on how to find the area of a parallelogram. I hope this helps you.