
What is the sum of the meausures of the interior angles of a polygon which has 20 diagonals


Ответы на вопрос

Ответ: .
Объяснение:
If the number of diagonals is 20, then the number of corners is:
Formula to find the sum of interior angles of a n-sided polygon:



To find the sum of the measures of the interior angles of a polygon with 20 diagonals, we can use the formula for the sum of the interior angles of a polygon:
Sum of Interior Angles = (n - 2) * 180 degrees
Where: - "n" is the number of sides of the polygon.
In this case, you want to find the sum of the interior angles of a polygon with 20 diagonals. Diagonals are line segments that connect non-adjacent vertices in a polygon.
We can use a formula to find the number of diagonals in a polygon based on the number of sides (n):
Number of Diagonals = [n(n - 3)] / 2
Now, you know that the number of diagonals is 20. So, we can set up the equation:
20 = [n(n - 3)] / 2
Let's solve for "n" by multiplying both sides by 2:
2 * 20 = n(n - 3)
40 = n^2 - 3n
Now, let's rearrange the equation to form a quadratic equation:
n^2 - 3n - 40 = 0
We can factor this equation:
(n - 8)(n + 5) = 0
Now, we have two possible solutions for "n":
1) n - 8 = 0, which gives n = 8 2) n + 5 = 0, which gives n = -5 (but since the number of sides of a polygon cannot be negative, we discard this solution)
So, the polygon has 8 sides (an octagon). Now we can use the formula for the sum of interior angles:
Sum of Interior Angles = (n - 2) * 180 degrees Sum of Interior Angles = (8 - 2) * 180 degrees Sum of Interior Angles = 6 * 180 degrees Sum of Interior Angles = 1080 degrees
The sum of the measures of the interior angles of the polygon is 1080 degrees.


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