Question

У трикутнику ΔBAC,CA=CB. Обчисли сторони трикутника, якщо основа трикутника на 150 мм більша від бічної сторони, його периметр △BAC дорівнює 1950 мм.

Answer 1

Ответ:

СА=СВ=Хмм

АВ=(Х+150)мм

Р=1950мм

х+х+х+150=1950

3х=1950-150

3х=1800

х=600

СА=СВ=600мм

АВ=600+150=750мм

Объяснение:

Answer 2

Given Information:

We are given that in triangle ΔBAC, CA = CB. The base of the triangle is 150 mm longer than the side, and the perimeter of triangle △BAC is 1950 mm.

Solution:

Let's assume that the length of the side of the triangle is x mm.

According to the given information, the base of the triangle is 150 mm longer than the side. Therefore, the length of the base can be expressed as (x + 150) mm.

The perimeter of a triangle is the sum of the lengths of its sides. In this case, the perimeter of triangle △BAC is given as 1950 mm. So we can write the equation:

x + x + (x + 150) = 1950

Simplifying the equation, we get:

3x + 150 = 1950

Subtracting 150 from both sides, we have:

3x = 1800

Dividing both sides by 3, we find:

x = 600

Therefore, the length of the side of the triangle is 600 mm.

To find the length of the base, we can substitute the value of x into the expression (x + 150):

600 + 150 = 750

So, the length of the base of the triangle is 750 mm.

To find the lengths of the other two sides, we can use the fact that CA = CB. Therefore, the lengths of the other two sides are also 600 mm.

In summary, the sides of the triangle are as follows: - The base of the triangle is 750 mm. - The other two sides of the triangle are 600 mm each.

Please let me know if I can help you with anything else.