Question

BC II AD,BC=4 AH=3 AD=?​

Answer 1

АD параллельно ВС ,значит АD=4

Answer 2

This appears to be a geometry problem involving a right triangle.

Let's first label the triangle. The right angle is at point A. Point B is on one leg of the triangle and point C is on the other leg. Point H is on the hypotenuse, which is the side opposite the right angle.

We are given that BC = 4 and AH = 3.

Using the Pythagorean theorem, we know that in a right triangle, the sum of the squares of the lengths of the legs is equal to the square of the length of the hypotenuse:

AC^2 + BC^2 = AH^2

We want to solve for AD, so we need to find the length of AC:

AC^2 = AH^2 - BC^2 AC^2 = 3^2 - 4^2 AC^2 = 9 - 16 AC^2 = -7

This doesn't make sense because the length of a side of a triangle cannot be negative. Therefore, this triangle cannot exist. Perhaps there was a typo or error in the problem statement.