Question

В сосуде находится смесь метана и ацетилена объем кислорода необходимый для полного сгорания этой смеси в 2,25 раза больше объема исходной смеси рассчитатйте состав смеси в объемных процентах

Answer 1

СH₄ + 2O₂ = CO₂ + 2H₂O
 vx

C₂H₂ + 2,5O₂ = 2CO₂ + H₂O
v(1-x)

по уравнениям реакций:
v₁(O₂)=2vx
v₂(O₂)=2,5v(1-x)

v(O₂)=2,25v=v₁+v₂

2,25v=2vx+2,5v(1-x)

x=0,5  объемная доля метана

w(CH₄)=w(C₂H₂)=0,5 (по 50%)

Answer 2

Calculation of Oxygen Volume:

To calculate the composition of the mixture in volumetric percentages, we first need to determine the volume of oxygen required for the complete combustion of the given mixture. According to the information provided, the volume of oxygen needed is 2.25 times the volume of the original mixture.

Let's assume the volume of the original mixture is V. Therefore, the volume of oxygen required for complete combustion is 2.25V.

Calculation of Methane and Acetylene Volumes:

Next, we need to determine the volumes of methane and acetylene in the original mixture. However, the exact composition of the mixture is not provided in the question. To proceed, we will make an assumption about the composition of the mixture.

Assumption: Let's assume that the original mixture contains equal volumes of methane and acetylene.

Therefore, the volume of methane in the original mixture is 0.5V, and the volume of acetylene is also 0.5V.

Calculation of Oxygen Volume in the Original Mixture:

Since the volume of oxygen required for complete combustion is 2.25V, and the volume of the original mixture is V, the volume of oxygen in the original mixture can be calculated as:

Oxygen Volume = 2.25V - V = 1.25V

Calculation of Volumetric Percentages:

To calculate the volumetric percentages of methane, acetylene, and oxygen in the original mixture, we need to divide the volume of each component by the total volume of the mixture and multiply by 100.

- Methane: (0.5V / V) * 100 = 50% - Acetylene: (0.5V / V) * 100 = 50% - Oxygen: (1.25V / V) * 100 = 125%

Please note that the calculated volumetric percentage of oxygen is greater than 100%. This indicates that the assumption made about the composition of the mixture is not valid. The given information suggests that the volume of oxygen required for complete combustion is 2.25 times the volume of the original mixture. However, the calculated volumetric percentage of oxygen exceeds 100%, which is not possible.

Therefore, it is not possible to determine the exact composition of the mixture in volumetric percentages based on the given information.