Question

Смесь пропана и бутана объемом 10 м ^ 3, с массовой долей пропана в ней 0.2 сожгли. Какой объем воздуха потратили? (Срочно)

Answer 1

Решение в фото...........:

Answer 2

Calculation of Air Volume Used

To calculate the volume of air used when burning a mixture of propane and butane, we need to consider the stoichiometry of the combustion reaction. The balanced equation for the combustion of propane is:

C3H8 + 5O2 -> 3CO2 + 4H2O

From this equation, we can see that 1 mole of propane reacts with 5 moles of oxygen to produce 3 moles of carbon dioxide and 4 moles of water.

Given that the volume of the mixture is 10 m^3 and the mass fraction of propane is 0.2, we can calculate the mass of propane and butane in the mixture.

Let's assume the molar mass of propane (C3H8) is 44 g/mol and the molar mass of butane (C4H10) is 58 g/mol.

The mass of propane in the mixture is: Mass of propane = Volume of mixture * Mass fraction of propane * Molar mass of propane Mass of propane = 10 m^3 * 0.2 * 44 g/mol

Similarly, the mass of butane in the mixture is: Mass of butane = Volume of mixture * (1 - Mass fraction of propane) * Molar mass of butane Mass of butane = 10 m^3 * (1 - 0.2) * 58 g/mol

Now, we can calculate the moles of propane and butane in the mixture by dividing their masses by their respective molar masses.

The moles of propane are: Moles of propane = Mass of propane / Molar mass of propane

The moles of butane are: Moles of butane = Mass of butane / Molar mass of butane

To determine the moles of oxygen required for complete combustion, we use the stoichiometry of the reaction. Since the molar ratio of propane to oxygen is 1:5, the moles of oxygen required are 5 times the moles of propane.

The moles of oxygen required are: Moles of oxygen = 5 * Moles of propane

Finally, we can calculate the volume of air used by multiplying the moles of oxygen by the molar volume of air at standard conditions, which is approximately 22.4 L/mol.

The volume of air used is: Volume of air used = Moles of oxygen * Molar volume of air Volume of air used = Moles of oxygen * 22.4 L/mol

Let's calculate the volume of air used based on the given information.