Question

какие объмы азота и водорода взяли для получения 44,8 л амиака: N2+H2=NH3

Answer 1

Напиши у лс, там помогу, тут мало времени

Answer 2

Calculating the Volume of Nitrogen and Hydrogen for the Production of 44.8 L of Ammonia (NH3)

To calculate the volumes of nitrogen (N2) and hydrogen (H2) required to produce 44.8 liters of ammonia (NH3) according to the chemical equation N2 + 3H2 = 2NH3, we can use the molar volume of gases at standard temperature and pressure (STP), which is 22.4 liters for 1 mole of any gas.

Using this information, we can calculate the volumes of N2 and H2 required.

Step 1: Calculate the moles of NH3 The balanced chemical equation shows that 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3.

Step 2: Calculate the moles of N2 and H2 From the stoichiometry of the reaction, we can determine the moles of N2 and H2 required to produce the given volume of NH3.

Step 3: Convert moles to volumes Finally, we can convert the moles of N2 and H2 to their respective volumes at STP.

Let's proceed with the calculations.

Calculations

Step 1: Calculate the moles of NH3 Given volume of NH3 = 44.8 L Molar volume of NH3 at STP = 22.4 L/mol

Moles of NH3 = Volume of NH3 / Molar volume of NH3 Moles of NH3 = 44.8 L / 22.4 L/mol Moles of NH3 = 2 moles

Step 2: Calculate the moles of N2 and H2 From the balanced chemical equation N2 + 3H2 = 2NH3, we can see that 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3.

Moles of N2 = 1/2 * Moles of NH3 Moles of N2 = 1/2 * 2 moles Moles of N2 = 1 mole

Moles of H2 = 3/2 * Moles of NH3 Moles of H2 = 3/2 * 2 moles Moles of H2 = 3 moles

Step 3: Convert moles to volumes Using the molar volume of gases at STP, we can convert the moles of N2 and H2 to their respective volumes.

Volume of N2 = Moles of N2 * Molar volume of N2 at STP Volume of N2 = 1 mole * 22.4 L/mol Volume of N2 = 22.4 L

Volume of H2 = Moles of H2 * Molar volume of H2 at STP Volume of H2 = 3 moles * 22.4 L/mol Volume of H2 = 67.2 L

Conclusion

To produce 44.8 liters of ammonia (NH3) according to the chemical equation N2 + 3H2 = 2NH3, we would need approximately: - 22.4 liters of nitrogen (N2) - 67.2 liters of hydrogen (H2)