
Вычислить молярную массу газа и его плотность при 40 градусах если 24 г его при 0 градусах и
давлении 2,026 * 10 в 5 степени па занимают объем 5,6 дм...

Ответы на вопрос

Плотность = PM/RT=(2,026*10^5*0,082)/(8,31*40)=49,9 кг/метр в кубе



Calculation of Molar Mass and Density of a Gas at 40 Degrees Celsius
To calculate the molar mass and density of a gas at 40 degrees Celsius, we need to use the ideal gas law equation, which relates the pressure, volume, temperature, and molar mass of a gas.
The ideal gas law equation is given as:
PV = nRT
Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature of the gas in Kelvin
To calculate the molar mass of the gas, we can rearrange the ideal gas law equation as follows:
Molar mass (M) = (mRT) / (PV)
Where: - M is the molar mass of the gas - m is the mass of the gas - R is the ideal gas constant - T is the temperature of the gas in Kelvin - P is the pressure of the gas - V is the volume of the gas
To calculate the density of the gas, we can use the formula:
Density (ρ) = (m) / (V)
Where: - ρ is the density of the gas - m is the mass of the gas - V is the volume of the gas
Now, let's calculate the molar mass and density of the gas at 40 degrees Celsius using the given information.
Given: - Mass of the gas at 0 degrees Celsius = 24 g - Pressure of the gas = 2.026 * 10^5 Pa - Volume of the gas = 5.6 dm^3
First, let's convert the temperature from Celsius to Kelvin: - Temperature at 40 degrees Celsius = 40 + 273.15 = 313.15 K
Now, we can calculate the molar mass using the formula mentioned earlier:
Molar mass (M) = (mRT) / (PV)
Substituting the given values: - m = 24 g - R = Ideal gas constant = 8.314 J/(mol·K) - T = 313.15 K - P = 2.026 * 10^5 Pa - V = 5.6 dm^3 = 5.6 * 10^-3 m^3
Calculating the molar mass: - M = (24 * 8.314 * 313.15) / (2.026 * 10^5 * 5.6 * 10^-3) = 0.028 kg/mol
Therefore, the molar mass of the gas is approximately 0.028 kg/mol.
Next, let's calculate the density using the formula mentioned earlier:
Density (ρ) = (m) / (V)
Substituting the given values: - m = 24 g = 0.024 kg - V = 5.6 dm^3 = 5.6 * 10^-3 m^3
Calculating the density: - ρ = 0.024 / (5.6 * 10^-3) = 4.286 kg/m^3
Therefore, the density of the gas at 40 degrees Celsius is approximately 4.286 kg/m^3.
Please note that the calculations provided are based on the ideal gas law and assume that the gas behaves ideally.


Топ вопросов за вчера в категории Химия
Последние заданные вопросы в категории Химия
-
Математика
-
Литература
-
Алгебра
-
Русский язык
-
Геометрия
-
Английский язык
-
Химия
-
Физика
-
Биология
-
Другие предметы
-
История
-
Обществознание
-
Окружающий мир
-
География
-
Українська мова
-
Информатика
-
Українська література
-
Қазақ тiлi
-
Экономика
-
Музыка
-
Право
-
Беларуская мова
-
Французский язык
-
Немецкий язык
-
МХК
-
ОБЖ
-
Психология
-
Физкультура и спорт
-
Астрономия
-
Кыргыз тили
-
Оʻzbek tili