Question

Задача не важка, але все ж таки прошу допомогти мені! Карбон (4) оксид об'ємом 33,6 л (н.у) пропустили через розчин, що містить натрій гідроксид масою 20 г. Знайти масу утвореної солі.

Answer 1

 здається отак
м(Na2CO3)= 53 г

Answer 2

Calculating the Mass of the Formed Salt

To calculate the mass of the formed salt, we can use the chemical equation for the reaction between carbon dioxide (CO2) and sodium hydroxide (NaOH). The balanced chemical equation for this reaction is:

CO2 + 2NaOH → Na2CO3 + H2O

From this equation, we can see that one mole of CO2 reacts with two moles of NaOH to produce one mole of Na2CO3 and one mole of H2O.

Given: - Volume of CO2 = 33.6 L (at standard conditions) - Mass of NaOH = 20 g

First, we need to calculate the number of moles of CO2 using the ideal gas law, and then use the mole ratio from the balanced chemical equation to find the moles of Na2CO3 formed. Finally, we can convert the moles of Na2CO3 to grams to find the mass of the formed salt.

Calculating Moles of CO2

Using the ideal gas law equation: PV = nRT

Where: P = pressure (at standard conditions, this is 1 atm) V = volume (33.6 L) n = number of moles R = ideal gas constant (0.0821 L.atm/mol.K) T = temperature (at standard conditions, this is 273 K)

We can rearrange the equation to solve for n: n = PV / RT

Substituting the given values: n = (1 atm) * (33.6 L) / (0.0821 L.atm/mol.K * 273 K)

Calculating n: n ≈ 1.33 moles

Calculating Moles of Na2CO3

From the balanced chemical equation, we know that 1 mole of CO2 reacts with 2 moles of NaOH to produce 1 mole of Na2CO3. Therefore, the moles of Na2CO3 formed will be half the moles of CO2 used in the reaction.

Moles of Na2CO3 = 1.33 moles / 2 Moles of Na2CO3 ≈ 0.67 moles

Calculating Mass of Na2CO3

The molar mass of Na2CO3 (sodium carbonate) is: Na = 22.99 g/mol C = 12.01 g/mol O = 16.00 g/mol

Molar mass of Na2CO3 = 2(22.99) + 12.01 + 3(16.00) = 105.99 g/mol

Now, we can calculate the mass of Na2CO3 formed: Mass = moles * molar mass Mass ≈ 0.67 moles * 105.99 g/mol Mass ≈ 71.01 g

The mass of the formed salt (sodium carbonate) is approximately 71.01 grams.