Question

C2H4-->C2H5 Cl-->C4H10-->C4H9Br-->C8H18-->C4H10-->CO2Напишите пожалуйста цепочку (реакции)

Answer 1

Из этилена хлорэтан получается при взаимодействии с хлороводородом:
1)С2Н4 + НСl=C2H5Cl
реакцией Вюрца получим бутан:
2)2C2H5Cl + 2Na = C4H10 + 2NaCl
добавим бром:
3)C4H10 + Br2 =C4H9Br + HBr
 и вновь реакция Вюрца:
4)  C4H9Br + 2Na= С8Н18 +2NaCl
алкан можно разложить под действием температуры и катализатора
5) С8Н18 =С4Н10+ С4Н8
алкан горит с выделением СО2 и Н2О
6)2С4Н10 + 13О2= 8СО2 + 10Н2О

Answer 2

Reaction Chain:

The given reaction chain involves a series of reactions starting with C2H4 and ending with CO2. Let's break down the reactions step by step:

1. C2H4 (Ethene) reacts with Cl to form C2H5Cl (Chloroethane): - C2H4 + Cl2 → C2H5Cl + HCl

2. C2H5Cl (Chloroethane) undergoes a substitution reaction to form C4H10 (Butane): - C2H5Cl + Na → C2H5Na + Cl - C2H5Na + C2H5Cl → C4H10 + NaCl

3. C4H10 (Butane) reacts with HBr to form C4H9Br (Butyl bromide): - C4H10 + HBr → C4H9Br + H2

4. C4H9Br (Butyl bromide) undergoes a substitution reaction to form C8H18 (Octane): - C4H9Br + Na → C4H9Na + Br - C4H9Na + C4H9Br → C8H18 + NaBr

5. C8H18 (Octane) undergoes a cracking reaction to form C4H10 (Butane): - C8H18 → C4H10 + C4H8

6. Finally, C4H10 (Butane) undergoes combustion to form CO2 (Carbon dioxide): - C4H10 + 6O2 → 4CO2 + 5H2O

So, the complete reaction chain is as follows: C2H4 → C2H5Cl → C4H10 → C4H9Br → C8H18 → C4H10 → CO2

Please note that the reaction equations provided are simplified representations of the reactions and may not include all the necessary conditions or reaction mechanisms.