Question

2)Разложение бертолетовой соли выражаеться уравнение КClO(3)=2KCl + 3O2Сколько литров кислорода выделиться при разложении 8 моль бертолетовой соли?

Answer 1

2КClO3=2KCl + 3O2
по стехиометрии из 2 моль берт/соли получается 3 моль кислорода, т.е. в полтора раза больше. Тогда из 8 моль получим 8*1.5 = 12 моль кислорода

Answer 2

Decomposition of Potassium Chlorate

The decomposition of potassium chlorate (KClO3) can be expressed by the following equation: 2KClO3 → 2KCl + 3O2

Calculation of Oxygen Gas Produced

To calculate the volume of oxygen gas produced when 8 moles of potassium chlorate decomposes, we can use the stoichiometry of the reaction.

According to the balanced chemical equation, 2 moles of potassium chlorate produce 3 moles of oxygen gas. Therefore, 1 mole of potassium chlorate produces \( \frac{3}{2} \) moles of oxygen gas.

Given that 8 moles of potassium chlorate are decomposing, the amount of oxygen gas produced can be calculated as follows: \( 8 \, moles \, KClO3 \times \frac{3 \, moles \, O2}{2 \, moles \, KClO3} = 12 \, moles \, O2 \)

Conversion to Liters

To convert moles of oxygen gas to liters at standard temperature and pressure (STP), we can use the molar volume of a gas at STP, which is approximately 22.4 liters per mole.

Therefore, the volume of oxygen gas produced when 8 moles of potassium chlorate decomposes is: \( 12 \, moles \, O2 \times 22.4 \, \frac{liters}{mole} = 268.8 \, liters \, O2 \)

So, 268.8 liters of oxygen gas will be produced when 8 moles of potassium chlorate decomposes.

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