Question

Вычислите массу (г) сульфата бария, который может быть получен при добавлении к 50 г 20,8% раствора хлорида бария серной кислоты, помогите пожалуйста, спасибо

Answer 1

Дано:m(р-ра BaCl2)=50г W(BaCl2)=20,8% Найти: m(BaSO4)=? Решение: BaCl2+H2SO4=BaSO4+2HCl m(BaCl2)=m(р-ра BCl2)*W(BaCl2)/100%=50*0,208=10,4г n(BaCl2)=m(BaCl2)/M(BaCl2)=10,4/208=0,05моль n(BaCl2):n(BaSO4)=1:1=0,05моль m(BaSO4)=n(BaSO4)*M(BaSO4)=0,05*233=11,65г Ответ:11,65г

Answer 2

Calculation of the Mass of Barium Sulfate

To calculate the mass of barium sulfate that can be obtained by adding sulfuric acid to a 50 g, 20.8% solution of barium chloride, we need to use the stoichiometry of the reaction between barium chloride and sulfuric acid.

The balanced chemical equation for the reaction is as follows:

BaCl2 + H2SO4 -> BaSO4 + 2HCl

From the equation, we can see that 1 mole of barium chloride reacts with 1 mole of sulfuric acid to produce 1 mole of barium sulfate.

To calculate the mass of barium sulfate, we need to determine the number of moles of barium chloride in the solution. We can then use the molar ratio between barium chloride and barium sulfate to calculate the mass of barium sulfate.

Calculation Steps:

1. Calculate the number of moles of barium chloride: - The given solution has a mass of 50 g and a concentration of 20.8%. - The concentration of a solution is defined as the mass of the solute divided by the mass of the solution, multiplied by 100. - Therefore, the mass of barium chloride in the solution is 20.8% of 50 g. - Convert the mass of barium chloride to moles using its molar mass.

2. Use the molar ratio between barium chloride and barium sulfate: - From the balanced chemical equation, we know that 1 mole of barium chloride reacts with 1 mole of barium sulfate. - Therefore, the number of moles of barium sulfate is equal to the number of moles of barium chloride.

3. Calculate the mass of barium sulfate: - Multiply the number of moles of barium sulfate by its molar mass to obtain the mass in grams.

Let's perform the calculations step by step.

Step 1: Calculate the number of moles of barium chloride:

The molar mass of barium chloride (BaCl2) is the sum of the atomic masses of its constituent elements: - Barium (Ba): 137.33 g/mol - Chlorine (Cl): 35.45 g/mol (x2, since there are two chlorine atoms in BaCl2)

The molar mass of BaCl2 is therefore 137.33 g/mol + 35.45 g/mol * 2 = 208.23 g/mol.

The mass of barium chloride in the solution is 20.8% of 50 g: - Mass of barium chloride = 20.8/100 * 50 g = 10.4 g.

To calculate the number of moles of barium chloride, divide the mass by the molar mass: - Number of moles of barium chloride = 10.4 g / 208.23 g/mol = 0.05 mol.

Step 2: Use the molar ratio between barium chloride and barium sulfate:

From the balanced chemical equation, we know that 1 mole of barium chloride reacts with 1 mole of barium sulfate.

Therefore, the number of moles of barium sulfate is equal to the number of moles of barium chloride, which is 0.05 mol.

Step 3: Calculate the mass of barium sulfate:

The molar mass of barium sulfate (BaSO4) is the sum of the atomic masses of its constituent elements: - Barium (Ba): 137.33 g/mol - Sulfur (S): 32.07 g/mol - Oxygen (O): 16.00 g/mol (x4, since there are four oxygen atoms in BaSO4)

The molar mass of BaSO4 is therefore 137.33 g/mol + 32.07 g/mol + 16.00