
Сколько граммов Са содержалось в смеси кальция и магния,если при взаиомдействии 16 грамм этой смеси
с избытком соляной кислоты выделилось 0.6 моль Н2. Ar(Ca)=40:Ar(Mg)=24

Ответы на вопрос

Сa +2HCl-> CaCl2 + H2 m(Ca)=40x
у у моль
Mg +2HCl-> MgCl2 + H2 m(Mg)=24y
Система:
x+y=0,6
40x+24y=16
40(0,6-y)+24y=16
x=0,1;
m(Ca)=0,1*40=4г



Calculating the Amount of Calcium in the Mixture
To calculate the amount of calcium in the mixture, we can use the given information about the reaction of the mixture with an excess of hydrochloric acid and the amount of hydrogen gas produced.
The balanced chemical equation for the reaction between calcium/magnesium mixture and hydrochloric acid is: Ca/Mg + 2HCl → CaCl2/MgCl2 + H2
From the given information, we know that 16 grams of the mixture reacted with an excess of hydrochloric acid and produced 0.6 moles of hydrogen gas.
Using the molar mass of calcium (Ca) and magnesium (Mg), we can calculate the amount of calcium in the mixture.
The molar mass of calcium (Ca) is 40 g/mol and the molar mass of magnesium (Mg) is 24 g/mol.
First, we need to find the moles of hydrogen gas produced: 0.6 moles H2
Now, we can calculate the moles of the reacted mixture: 16 grams / (40 g/mol + 24 g/mol) = x moles
Calculating the Amount of Calcium in the Mixture
To find the moles of calcium in the reacted mixture, we can use the molar ratio between calcium and hydrogen gas in the balanced chemical equation.
The molar ratio between calcium and hydrogen gas is 1:1 in the balanced chemical equation: Ca/Mg + 2HCl → CaCl2/MgCl2 + H2
Therefore, the moles of calcium in the reacted mixture are equal to the moles of hydrogen gas produced: x moles Ca
Now, we can calculate the mass of calcium in the reacted mixture: x moles Ca * 40 g/mol = y grams Ca
So, the amount of calcium in the mixture is y grams.
Let's calculate the value of x and y using the given information.


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