Question

По уравнению реакции 2Na+2H2O=2NaOH+H2 Рассчитайте, какая масса натрия потребуется для реакции 3,6 г воды. Какой объем водорода при этом образуется? Ребзя,помогите,пожалуйста!!

Answer 1

Здесь ничего сложного
2Na+2H2O=2NaOH+H2
"Какая масса потребуется?"-намекает на равное кол-во в-ва(как-бы нужного)
n(H2O)=m/M=3.6/18=0.2 моль
n(Na)=n(H2O)-по реакции
m(Na)=n*M=0.2*23=4,6г-искомое
n(H2)=1/2n(H2O)=0.1 моль
V(H2)=n*Vm=0.1 моль*22,4л/моль=2,24л

Answer 2

Calculation of the Mass of Sodium Required:

To calculate the mass of sodium required for the reaction, we need to use the stoichiometry of the balanced equation. The balanced equation for the reaction is:

2Na + 2H2O → 2NaOH + H2

According to the equation, 2 moles of sodium react with 2 moles of water to produce 2 moles of sodium hydroxide and 1 mole of hydrogen gas.

To find the mass of sodium required, we can use the molar mass of sodium, which is approximately 22.99 g/mol.

Given that the mass of water is 3.6 g, we can calculate the number of moles of water using its molar mass, which is approximately 18.02 g/mol.

Number of moles of water = mass of water / molar mass of water Number of moles of water = 3.6 g / 18.02 g/mol

Now, since the stoichiometric ratio between water and sodium is 2:2, we can say that the number of moles of sodium required is equal to the number of moles of water.

Number of moles of sodium = number of moles of water

Therefore, the mass of sodium required can be calculated as follows:

Mass of sodium = number of moles of sodium × molar mass of sodium Mass of sodium = (3.6 g / 18.02 g/mol) × 22.99 g/mol

Let's calculate the mass of sodium using the given values:

Mass of sodium = (3.6 g / 18.02 g/mol) × 22.99 g/mol

Calculating this expression gives us the mass of sodium required for the reaction.

Calculation of the Volume of Hydrogen Produced:

To calculate the volume of hydrogen gas produced, we can use the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles of the gas.

According to the balanced equation, 2 moles of sodium react to produce 1 mole of hydrogen gas. Therefore, the number of moles of hydrogen gas produced is half the number of moles of sodium.

Number of moles of hydrogen gas = 1/2 × number of moles of sodium

Using the number of moles of sodium calculated earlier, we can find the number of moles of hydrogen gas produced.

Now, we can use the ideal gas law equation:

PV = nRT

Where: P = pressure (assumed to be constant) V = volume of gas n = number of moles of gas R = ideal gas constant T = temperature (assumed to be constant)

Since the pressure, gas constant, and temperature are assumed to be constant, we can rewrite the equation as:

V = (n × R × T) / P

Given that the volume of hydrogen gas is the unknown, we can rearrange the equation to solve for V:

V = (number of moles of hydrogen gas × R × T) / P

Now, let's calculate the volume of hydrogen gas using the given values:

V = (number of moles of hydrogen gas × R × T) / P

Calculating this expression gives us the volume of hydrogen gas produced.

Please note that the actual values of pressure and temperature are not provided in the question, so we cannot calculate the exact volume of hydrogen gas without this information.