Question

Какое количество вещества кислорода необходимо для окисления 2 моль фосфора по уравнению 4P + 5O^2 = 2P^2O^5

Answer 1

2 моль(фосфора) умножить на 5 моль кислорода и все это разделить на 4 моля фосфора получим 2,5 моль кислорода, что и является ответом

Answer 2

Calculating the Amount of Oxygen Required to Oxidize 2 Moles of Phosphorus

To calculate the amount of oxygen required to oxidize 2 moles of phosphorus according to the equation 4P + 5O2 = 2P2O5, we can use stoichiometry to determine the molar ratio of phosphorus to oxygen.

According to the balanced chemical equation, 4 moles of phosphorus react with 5 moles of oxygen to produce 2 moles of P2O5.

Therefore, the amount of oxygen required to oxidize 2 moles of phosphorus can be calculated as follows:

Step 1: Determine the molar ratio of phosphorus to oxygen from the balanced chemical equation: - 4 moles of P : 5 moles of O2

Step 2: Use the molar ratio to calculate the amount of oxygen required: - (5 moles of O2 / 4 moles of P) * 2 moles of P = 2.5 moles of O2

Therefore, 2.5 moles of oxygen are required to oxidize 2 moles of phosphorus according to the given chemical equation.

Cited Sources

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