Question

1)KOH+H3PO4= 2)NA2SiO3+HCL

Answer 1

1.Реакция нейтрализации(взаимодействие щелочи с кислотой,в результате чего образуется соль и вода)
3KOH+H3PO4----->K3PO4+3H2O
2.Реакция обмена
Na2SiO3+2HCL----->2NaCL+SiO2+H2O

Answer 2

1) 3KOH + H3PO4 = K3PO4 + 3H2O
2) Na2SiO3 + 2HCl ---> 2NaCl + H2SiO3

Answer 3

1) KOH + H3PO4:

The reaction between potassium hydroxide (KOH) and phosphoric acid (H3PO4) is a neutralization reaction. In this reaction, the potassium hydroxide reacts with the phosphoric acid to form potassium phosphate (K3PO4) and water (H2O).

The balanced chemical equation for this reaction is:

3 KOH + H3PO4 -> K3PO4 + 3 H2O

In this equation, you can see that three molecules of potassium hydroxide react with one molecule of phosphoric acid to produce one molecule of potassium phosphate and three molecules of water.

2) Na2SiO3 + HCl:

The reaction between sodium silicate (Na2SiO3) and hydrochloric acid (HCl) is an acid-base reaction. In this reaction, the hydrochloric acid reacts with the sodium silicate to form sodium chloride (NaCl) and silicic acid (H4SiO4).

The balanced chemical equation for this reaction is:

Na2SiO3 + 2 HCl -> 2 NaCl + H4SiO4

In this equation, you can see that one molecule of sodium silicate reacts with two molecules of hydrochloric acid to produce two molecules of sodium chloride and one molecule of silicic acid.

It's important to note that silicic acid is not stable and tends to undergo further reactions to form various silicon-containing compounds or polymerize to form silicon dioxide (SiO2).

Please let me know if you need any further clarification.