Question

Углекислый газ получают разложением карбоната кальция массой 200г. Выход продукта составляет 80%. Рассчитайте, какой объем (н.у) кислорода будет затрачен для получения углекислого газа при сжигании метана.

Answer 1

1.Ответ во вложении.

Answer 2

Calculation of Oxygen Volume Required for Carbon Dioxide Production

To calculate the volume of oxygen required for the production of carbon dioxide through the combustion of methane, we need to consider the stoichiometry of the reaction and the molar masses of the compounds involved.

The balanced equation for the combustion of methane (CH4) is as follows:

CH4 + 2O2 → CO2 + 2H2O

From the equation, we can see that one molecule of methane reacts with two molecules of oxygen to produce one molecule of carbon dioxide and two molecules of water.

Given that the mass of calcium carbonate (CaCO3) is 200g and the yield of the product is 80%, we can calculate the mass of carbon dioxide produced:

Mass of carbon dioxide = Mass of calcium carbonate × Yield of product

Mass of carbon dioxide = 200g × 0.8 = 160g

Next, we need to convert the mass of carbon dioxide to moles using the molar mass of carbon dioxide. The molar mass of carbon dioxide (CO2) is approximately 44g/mol.

Number of moles of carbon dioxide = Mass of carbon dioxide / Molar mass of carbon dioxide

Number of moles of carbon dioxide = 160g / 44g/mol ≈ 3.64 mol

According to the stoichiometry of the balanced equation, we know that one mole of carbon dioxide is produced from two moles of oxygen. Therefore, the number of moles of oxygen required can be calculated as follows:

Number of moles of oxygen = 2 × Number of moles of carbon dioxide

Number of moles of oxygen = 2 × 3.64 mol ≈ 7.28 mol

Finally, we can use the ideal gas law to calculate the volume of oxygen required at standard temperature and pressure (STP). STP is defined as a temperature of 0 degrees Celsius (273.15 Kelvin) and a pressure of 1 atmosphere (101.325 kilopascals).

The ideal gas law equation is as follows:

PV = nRT

Where: - P is the pressure (in pascals) - V is the volume (in cubic meters) - n is the number of moles - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature (in Kelvin)

At STP, the pressure is 101.325 kilopascals and the temperature is 273.15 Kelvin.

Rearranging the ideal gas law equation to solve for volume, we have:

V = (nRT) / P

Substituting the values into the equation, we can calculate the volume of oxygen required:

V = (7.28 mol × 8.314 J/(mol·K) × 273.15 K) / 101.325 kPa

Calculating this expression gives us the volume of oxygen required in cubic meters.

Please note that the calculation assumes ideal gas behavior and does not account for any non-ideal factors that may affect the volume of oxygen required.