Question

Br2+2Nai=2NaBr+I2 ОВР надо сделать помогите плизз

Answer 1

Вот, лови решение) на фотографии все

Answer 2

Chemical Equation

According to the chemical formula provided, this reaction can be written as:

Br2 + 2Na → 2NaBr + I2

The bromine (Br2) and sodium (Na) react to form sodium bromide (NaBr) and iodine (I2).

Balancing the Chemical Equation

To balance the chemical equation, we need to determine the coefficients of the reactants and products so that the number of each type of atom is equal on both sides of the equation.

For bromine (Br): - Left side: 2 Br atoms - Right side: 2 Br atoms

For sodium (Na): - Left side: 2 Na atoms - Right side: 2 Na atoms

For iodine (I): - Left side: 0 I atoms - Right side: 2 I atoms

Therefore, the chemical equation is already balanced and the coefficients are correct as written.

Oxidation-Reduction (Redox) Reaction

This reaction also involves a transfer of electrons, so it is considered an oxidation-reduction or redox reaction. Specifically: - Bromine (Br2) is being reduced, gaining electrons to form bromide (Br-) - Sodium (Na) is being oxidized, losing electrons to form sodium ions (Na+)

In a redox reaction, the element being reduced acts as the oxidizing agent while the element being oxidized acts as the reducing agent. So in this case: - Bromine (Br2) acts as the oxidizing agent - Sodium (Na) acts as the reducing agent

I hope this helps explain the reaction and balancing process. Let me know if you have any other questions!